A satellite of mass m orbits a planet of mass m in a circular orbit of radius bR. The time required for one revolution is
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ANSWER
Given satelite mass =m
Radius =R
Planet mass =M
circular orbit radius =r
velocity of (v) of satelite v=
r
GM
KE=
2
1
mv
2
=
2
1
m(
r
GM
)
PE=
2r
−GMm
E=KE+PE=
2r
−GMm
Angular momentum (L)
L=mvr
=m(
r
GM
)r
=m
GMr
∵ direction of L is perpendicular to the plane of the orbit.
Explanation:
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