a satellite of mass M revolves around the earth of radius R at height H from its surface if g is the acceleration due to gravity on the surface of earth the orbital velocity of speed is
Answers
Answered by
0
An Earth satellite of mass m revolves in a circular orbit at a height h from the surface of Earth. If E is the radius and g is the acceleration due to gravity, what is the velocity of the satellite in its orbit?
Answer
67
Follow
Request
More
Ad by Atlassian
Do you use Jira or Confluence in the field of education?
Come to Atlassian Community and you might be inspired. Connect, share, and learn.
Learn More
2 ANSWERS

Samyak Jain, Hobby and aim
Answered Aug 17, 2017
Answer will be √(GM/h+E) where M is the mass of earth, G is the gravitational constant.
The velocity is independent of mass of the satellite.
For derivation compare the gravitational and centripetal forces
I.e.
let mass of object=m and mass of earth=M, total height =h+E=r
Centripetal force = gravitational force
0.mv^2/r=m x GM/(r^2)
Solve for V
You will get v^2=GM/R
So v=√(GM/R)
Also if you want to calculate in terms of acceleration due to gravity put g=GM/(r^2)
Answer
67
Follow
Request
More
Ad by Atlassian
Do you use Jira or Confluence in the field of education?
Come to Atlassian Community and you might be inspired. Connect, share, and learn.
Learn More
2 ANSWERS

Samyak Jain, Hobby and aim
Answered Aug 17, 2017
Answer will be √(GM/h+E) where M is the mass of earth, G is the gravitational constant.
The velocity is independent of mass of the satellite.
For derivation compare the gravitational and centripetal forces
I.e.
let mass of object=m and mass of earth=M, total height =h+E=r
Centripetal force = gravitational force
0.mv^2/r=m x GM/(r^2)
Solve for V
You will get v^2=GM/R
So v=√(GM/R)
Also if you want to calculate in terms of acceleration due to gravity put g=GM/(r^2)
Answered by
2
Answer:
hope it helps
please mark as brainliest
Attachments:
Similar questions