Question

A satellite of mass mis orbiting a planet of radius R. at
a heighth from its surface. The kinetic energy of
satellite in terms of the value of acceleration due to
gravity at the planet's surface is​

Answer 1

Explanation:

Total energy of the satellite T=

2r

−GMm

where r=R+h

∴ T=

2(R+h)

−GMm

Acceleration due to gravity at earth's surface g

o

=

R

2

GM

⟹GM=g

o

R

2

⟹ T=

2(R+h)

−mg

o

R

2