Question

A satellite of mass Mo is revolving around the
earth is circular orbit at a height of 3R from
surface of earth. The areal velocity of satellite
is (where R is radius of earth and Me is mass
of earth)
Zero
O
GM R
GM,R
O
V4GM R​

Answer 1

Explanation:

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Answer 2

Given:

the radius of earth = R

mass  of earth = Me

mass  of Satellite = Mo

height of  from  the surface of earth =3R

To Find:

the areal velocity of satellite =?

Solution:

we know that the expression to calculate the orbital velocity of the satellite,

orbital velocity (v) = $\sqrt{\dfrac{GMe}{R +h} }$

here, h = height from the surface of the earth =3R

orbital velocity (v) = $\sqrt{\dfrac{GMe}{4R} }$

now, we also know the expression to calculate the areal velocity,

areal velocity = $\dfrac{v \times r}{2}$

here, r = height from the centre of the earth =3R + R = 4R

On putting values,

areal velocity = $\dfrac{\sqrt{\dfrac{GMe}{4R} } \times 4R}{2}$

Areal velocity = $\sqrt{GMeR}$