A satellite of mass orbits earth in an elliptical orbit having apehelion distance is ra
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For a satellite, moving in a circular orbit, to remain in equilibrium around the Earth it is required that the centripetal force acting outwards equals the gravitational force acting between them.
So,
mv2/r = mw2r = GMm/r2
here
m is the mass of the satellite
M is the mass of the Earth
r is the radius of separation
and
w is the angular velocity
so, by multiplying both sides of the equation by 'm' and by 'r3', we get
(mwr)2 = GMm2r
or
as L = mrw
we have
L2 = GMm2r
or finally, the angular momentum of a satellite in a circular orbit would be
L = [GMm 2 r]1/2
So,
mv2/r = mw2r = GMm/r2
here
m is the mass of the satellite
M is the mass of the Earth
r is the radius of separation
and
w is the angular velocity
so, by multiplying both sides of the equation by 'm' and by 'r3', we get
(mwr)2 = GMm2r
or
as L = mrw
we have
L2 = GMm2r
or finally, the angular momentum of a satellite in a circular orbit would be
L = [GMm 2 r]1/2
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