Question

a satellite of radius R is rotating in a circular orbitwhat will be the percentage change in the time of its radius is increased to 1.002R​

Answer 1

Answer:

Time Period = 2π√R/g

T ~ √R

∆T/T = 1/2 ∆R/R

∆R = 1.002R

∆T/T % = 50.1%

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