Question

A satellite revolves in a circular orbit at a height 200 km from the surface of the earth.If the time period of revolution of satellite is 90 mins,find density of earth if G=6.67*10^-11 Nm^2kg^-2 and radius of earth is 6*10^6 m

Answer 1

Answer:

Let the mass of satellite be m and velocity be v.

Distance b/w satellite and center of earth,r=6400+1000=7400

The necessary centripetal force for satellite to revolve around the earth is  given by the gravitational attraction b/w earth and satellite  

i.e 

v=2 *10⁶ ans .....