A satellite which is geostationary in a particular Orbit it take it to another Orbit its distance from the centre of earth in new orbit is two time than that earlier orbit the time period of second orbit is
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hello mate___ your ans is here__☺
we know that that:-
T is proportional to r^3/2
so in following case this equation
can be made:-
t1/t2 = (r1^3/2)/ (r2^3/2)
Solving this further....
t1/t2 =( 1/2) ^3/2
t2 = t1 × 2^3/2
t2 = 2√2 t1
so time period of 2nd orbit is 2√2 times to 1st orbit.
i hope ,this will be help full 4 u__
thank you( special tq 4 my frd ,who hepl me to solve this question!!)
✒ Be Brainly
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soumya2302:
mstt ans bro ❤❤
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