Physics, asked by gopalkumar32205, 11 months ago

A satellite which is geostationary in a particular Orbit it take it to another Orbit its distance from the centre of earth in new orbit is two time than that earlier orbit the time period of second orbit is

Answers

Answered by Anonymous
15

hello mate___ your ans is here__☺

we know that that:-

T is proportional to r^3/2

so in following case this equation

can be made:-

t1/t2 = (r1^3/2)/ (r2^3/2)

Solving this further....

t1/t2 =( 1/2) ^3/2

t2 = t1 × 2^3/2

t2 = 2√2 t1

so time period of 2nd orbit is 2√2 times to 1st orbit.

i hope ,this will be help full 4 u__

thank you( special tq 4 my frd ,who hepl me to solve this question!!)

✒ Be Brainly

__________________________________


soumya2302: mstt ans bro ❤❤
Anonymous: ❤❤nyc bestie
Anonymous: ^_^❤ TQ ☺
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