Question

A saturated clay specimen has the water content of 36% and particle specified gravity of 2.70 . Determine the void ratio and dry density.​

Answer 1

Answer:

Explanation:

e= W sat. G Therefore e=0.36G Now mass specific gravity  Gm=[(G+e).Yw/(1+e)].(1/Yw)  Therefore 1.86=[(G+0.36G)/(1+0.36)1.86=1.36G/(1+0.36G)G=2.69 Now.