Question

a saturated made by dissolving 200 grams of the same sugar in 100 ml of water at 25 degrees celsius?
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Answer 1

Answer:

A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution.

Increased temperature usually increases the solubility of solids in liquids.

For example, the solubility of glucose at 25 °C is 91 g/100 mL of water. The solubility at 50 °C is 244 g/100 mL of water.

If we add 100 g of glucose to 100 mL water at 25 °C, 91 g dissolve. Nine grams of solid remain on the bottom. We have a saturated solution.

If we now heat the mixture to 50 °C, the remaining 9 g of glucose will dissolve. At the new temperature, the solubility limit in 100 mL of water is 244 g glucose. With only 100 g of glucose dissolved, the solution is now unsaturated.

If we next cool the mixture back to 25 °C, 9 g of glucose should precipitate from solution.

If glucose crystals do not form, the system has more dissolved glucose (100 g) than it can hold at 25 °C (91 g). We have a supersaturated solution.

The first step in the formation of crystals is nucleation. This is when the solute molecules arrange themselves to form crystals.

Sometimes this happens at once. If it doesn't, we have a supersaturated solution. This is an unstable situation.

A piece of dust or a small crystal of the solute, a seed crystal, provides a template for crystallization of the excess solute. The excess solute starts to form crystals on the nuclei.

Once crystals start to form, their surface area increases as they grow. This attracts more molecules and promotes growth at an ever-increasing rate. Finally, the solution stabilizes and no more crystals can form.

Answer 2

Answer:

The explanation for the question is given below.

Explanation:

The other name of Sugar is Sucrose.

If the temperature increases more sugar will be dissolved in water.

• At 0°C, 179 grams of sugar will dissolve in 100 ml water.
• At 20°C, 204 grams of sugar will dissolve in 100ml water.
• At 40°C, 241 grams of sugar will dissolve in 100 ml water.
• At 50°C about 260 grams of sugar will dissolve in 100ml water.

The solubility of sugar is 2000 grams in 1 liter of water to make the solution saturated at 25°C.

Based on the inter molecular force and entropy the solubility of the solute was determined.

If the temperature increases the solubility of solute in solvent also increases.

Therefore, to make the solution saturated the 200 grams of sugar will dissolve in 100 ml of water at 25°C.

To find the concentration of the solution:

Given:

• Weight of sugar = 200 grams
• Volume of water = 100 ml
• We know that 1 ml of water = 1 gram of water
• Therefore, 100 ml of water = 100 grams of water
• Mass of total solution = 200 + 100 = 300 grams
• Temperature = 25°C

To find:

The concentration of the mass

Solution:

$Mass = \frac{Mass of solute}{Mass of Solution} * 100\\ \\Mass = \frac{200}{300} * 100$

Mass = 66.66%

The concentration of the solution is 66.66%

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