Question

. A saturated solution containing 400 kg of KCl at 360 K is cooled to 290 K in an open tank. The solubility of KCl at 360 K and 290 K are 43.55 kg KCl/100 kg H2O and 34.5 kg KCl/100 kg H2O, respectively. The specific gravity of the solution is 1.17. Calculate: a. Volume of the tank (in m3). b. Amount of crystals formed if 22% of the total water is vaporized.

Answer 1

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ANSWER:-A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution.

A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution.Increased temperature usually increases the solubility of solids in liquids.

A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution.Increased temperature usually increases the solubility of solids in liquids.For example, the solubility of glucose at 25 °C is 91 g/100 mL of water. The solubility at 50 °C is 244 g/100 mL of water.

A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution.Increased temperature usually increases the solubility of solids in liquids.For example, the solubility of glucose at 25 °C is 91 g/100 mL of water. The solubility at 50 °C is 244 g/100 mL of water.If we add 100 g of glucose to 100 mL water at 25 °C, 91 g dissolve. Nine grams of solid remain on the bottom. We have a saturated solution.

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