A saturn year is 29.5 times the earth year. How far is saturn from the sun(m) if the earth is 1.5 x 108 km away from the sun ?
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Answer:
Solution : Here, `T_(s) = 29.5 T_(e) , R_(e) = 1.5 xx 10^(8) km, R_(s) = ?`<br> Using the relation, `(T_(s)^(2))/(T_(s)^(3)) = (T_(e)^(2))/(R_(e)^(3)) `or `R_(s) = R_(e) ((T_(s))/(T_(e)))^(2//3) = 1.5 xx 10^(8) ((29.5 T_(e))/(T_(e)))^(2//3) = 1.43 xx 10^(9) km`
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WE KNOW THAT
Distance of the Earth from the Sun, re = 1.5 × 10⁸ km = 1.5 × 10¹¹m.
SOLUTION
» Time period of the Earth = Te
» Time period of Saturn, Ts = 29. 5 Te
» Distance of Saturn from the Sun = rs
† From Kepler’s third law of planetary motion, we have
» T = √(4π²r³ / GM)
† For Saturn and Sun, we can write
» rs³ / re³ = Ts² / Te²
» rs = re(Ts / Te)²/³
= 1.5 × 1011 (29.5 Te / Te)²/³
= 1.5 × 1011 (29.5)²/³
= 14.32 × 10¹¹ m
★ Hence, the distance between Saturn and the Sun is 1.43 × 10¹² m.
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