A savlo train starting from stationaery position and moving with uniform acceleration attains a speed of 36km /h in 10 min .find its acceleration sovlo numerical
Answers
A savlo train starting from stationaery position and moving with uniform acceleration attains a speed of 36km /h in 10 min .find its acceleration sovlo numerical
Cᴏᴘɪᴇᴅ :-)
Given :
- Initial velocity of the train = 0 m/s (Because it started from stationary position.)
- Final velocity of the train = 36 km/h
- Time taken = 10 minutes
- The train moves with uniform acceleration
To find :
- Acceleration
Solution :
Firstly, convert the velocity of the train from km/h into m/s :
→ Final velocity = 36 km/h
Multiply the value by 5/18 to convert it into m/s.
→ Final velocity = 36 × 5/18
→ Final velocity = 2 × 5
→ Final velocity = 10
Therefore, the final velocity of the train = 10 m/s.
Now, convert the time from minutes into seconds :
→ Time = 10 minutes
As we know,
- 1 minute = 60 seconds
Mulitply the value by 60 to convert it from minutes into seconds.
→ Time = 10 × 60
→ Time = 600
Therefore, time taken by the train = 600 seconds.
To calculate the acceleration of the train, use the first equation of motion :
First equation of motion :
- v = u + at
where,
• v denotes the final velocity
• u denotes the initial velocity
• a denotes the acceleration
• t denotes the time
we have,
- v = 10 m/s
- u = 0 m/s
- a = ?
- t = 600 s
Substituting the given values :
→ 10 = 0 + a × 600
→ 10 = a × 600
→ 10/600 = a
→ 1/60 = a
→ 0.0167 = a
Therefore, the uniform acceleration of the train = 1/60 m/s² or 0.0167 m/s²
⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━
About equations of motion :
Second equation of motion :
- s = ut + ½ at²
Third equation of motion :
- v² - u² = 2as
where,
• s denotes the displacement/distance