A says to B I am 5 times as old as you were when I was old as you. The sum of their present ages is 64 years. Find their present ages.
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Hi friend, Here is the required answer :-
Let the age of A be x.
And the age of B be y.
Then, x+y=64
Multiplying by 6,
6x=384-6y ............ (1)
Now, (x-y) is the difference between the ages.
So atq, x =5(y-(x-y))
x=5 ( y-x+y)
x=10y-5x
6x=10y............(2)
Subtracting both the equation.
6x-6x=384-6y-10y
0=384-16y
16y=384
y=24.
The ages are of A and B are 40 & 24 respectively.
Hope this helps you...
PLEASE MARK AS BRAINLIEST ANSWER!
Let the age of A be x.
And the age of B be y.
Then, x+y=64
Multiplying by 6,
6x=384-6y ............ (1)
Now, (x-y) is the difference between the ages.
So atq, x =5(y-(x-y))
x=5 ( y-x+y)
x=10y-5x
6x=10y............(2)
Subtracting both the equation.
6x-6x=384-6y-10y
0=384-16y
16y=384
y=24.
The ages are of A and B are 40 & 24 respectively.
Hope this helps you...
PLEASE MARK AS BRAINLIEST ANSWER!
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