Math, asked by tabbhjkohg, 1 year ago

A says to B I am twice as old as you were when I was as old as you are ." The sum of their present ages is 63

Answers

Answered by AbiZ
2

Answer:

Step-by-step explanation:

Attachments:
Answered by hotelcalifornia
16

Answer:

The present ages of A and B is 36 and 27 years respectively.

Solution:

Let A’s present age be x

Then B’s present age = 63 – x

And when A = (63 –x)

\begin{array} { c } { A - B = 2 x - 63 } \\\\ { ( 63 - x ) - B = 2 x - 63 } \\\\ { B = 126 - 3 x } \end{array}

Thus we know that, A’s age is twice as B’s. so,

\begin{array} { c } { x = 2 ( 126 - 3 x ) } \\\\ { 7 x = 252 } \\\\ { x = \frac { 252 } { 7 } = 36 } \end{array}

So A’s age is 36 years  

And B’s age is equal to 63 – 36 i.e., 27 years.  

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