A says to B,"I am twice as old as you were, when I was as old as you are". If the sum of their ages is 70 years then, find their present age
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Answered by
1
Answer: Let A's present age= x years
B's present age= (70-x) years
Difference between their ages= x-(70-x)
= x-70+x
= 2x-70
When A's age was (70-x) years
Then B's age was (A's age - Difference of their ages) = 70-x-(2x-70) = 70-x-2x+70
= (140-3x) years
According to the question,
A's present age = 2(B's past age)
x = 2(140-3x)
x = 280-6x
x+6x = 280
7x = 280
x = 280/7
x = 40
A's present age= x = 40 years
B's present age= (70-x) = (70-40) = 30 years
Answered by
1
Answer:
b=23.3333333333 or 23
a=46.6666666667 or 47
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