a says to b I am twice as old as you were when i was as old as you are. the sum of their age is 63 years. find the difference of their ages
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Here is your answer,
Let the present ages of A and B be a and b respectively
A says to B "I am twice as old as you were when I was as old as you are".
=> A's age = 2 × (B's age when A's age was equal to B's age)
=> A's age = 2 × (B's age when A's age was b)
=> a = 2[b - (a-b)]
=> a = 2(b - a + b)
=> a = 2(2b - a)
=> a = 4b - 2a
=> 3a - 4b = 0 ---(1)
Given
a + b = 63 ---(2)
Solve (1) and (2).
(2)×3 - (1) => 7b = 189
=> b = 27
From(1), 3a - 4×27 = 0
=> a - 36 = 0
=> a = 36
Required difference = (a - b) = 36 - 27 = 9
Hope it helps you!
Here is your answer,
Let the present ages of A and B be a and b respectively
A says to B "I am twice as old as you were when I was as old as you are".
=> A's age = 2 × (B's age when A's age was equal to B's age)
=> A's age = 2 × (B's age when A's age was b)
=> a = 2[b - (a-b)]
=> a = 2(b - a + b)
=> a = 2(2b - a)
=> a = 4b - 2a
=> 3a - 4b = 0 ---(1)
Given
a + b = 63 ---(2)
Solve (1) and (2).
(2)×3 - (1) => 7b = 189
=> b = 27
From(1), 3a - 4×27 = 0
=> a - 36 = 0
=> a = 36
Required difference = (a - b) = 36 - 27 = 9
Hope it helps you!
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