Physics, asked by ishita122, 1 year ago

a scale is divided into 0.5 mm division. if 20 divisions of this scale are divided into 25 equal parts of a vernier calculate the least count

Answers

Answered by Deepsbhargav
34
hey friend!!!

Solution:

1 M.S.D. = 0.5 mm

25 V.S.D. = 20 M.S.D.

Thus,

1 V.S.D. = 20/25 M.S.D. = 0.8 M.S.D. = 0.8 x 0.5 mm = 0.4 mm

Now, Least Count of Vernier Caliper = 1 M.S.D. – 1.V.S.D. = 0.5 mm – 0.4 mm = 0.1 mm

Hence least count of vernier calliper is "0.1 mm"

hope it will help you..
Answered by liquissingh
3

Answer:

0.1 mm

CONVERSION

0.01cm ans.

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