A school auditorium is 50m long & 30m wide. this auditorium is surrounded by a veranda 5m wide on the outside of it. find the area of veranda?find the area of verandah if tiles of 5ocm*50cm fixed on the verandah hoe many tiles are required
Answers
Answered by
7
length of veranda=50m=5000cm
breadthh=30m=3000cm
area ofveranda=l*b=5000*3000=15000.
area of tile=50*50=2500cm
no of tiles=15000/2500
=6000.
breadthh=30m=3000cm
area ofveranda=l*b=5000*3000=15000.
area of tile=50*50=2500cm
no of tiles=15000/2500
=6000.
adithya7:
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man ur answer is wrong
cuz the length and breadth of the SCHOOL AUDITORIUM is 50 & 30m respectively
Answered by
18
the area of school autitorium = 50×30
=1500m²
the whole figure obtained is a rectangle
the length of this rectange= 50+5+5=60
its breadth=30+5+5=40
its area = 60×40=2400 m²
area of varanda=area of whole figure-area of auditorium.
area of varanda=2400-1500
=900m²
area of tiles = 0.5 × 0.5
=0.25m²
∴number of tiles required= 2400/0.25
=240000/25
9600
∴ number of tiles required to tile the varanda = 9600
hope it helps and pls mark as best answer
=1500m²
the whole figure obtained is a rectangle
the length of this rectange= 50+5+5=60
its breadth=30+5+5=40
its area = 60×40=2400 m²
area of varanda=area of whole figure-area of auditorium.
area of varanda=2400-1500
=900m²
area of tiles = 0.5 × 0.5
=0.25m²
∴number of tiles required= 2400/0.25
=240000/25
9600
∴ number of tiles required to tile the varanda = 9600
hope it helps and pls mark as best answer
plz mark this as brainliest
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