Question

A school borrows an amount of Rs 1,00,000 from a bank to construct a Mathematics laboratory
The loan is taken on compound interest, compound annually at the rate of 8% per annum Find the
amount paid back at the end of 3
years,​

Answer 1

Answer:

• amount= principal x
• ${(1 + rate)}^{n}$

Step-by-step explanation:

amount= 1,00,000(1+8/100)^3

A= 100000 (108/100)^3

A= 100000 (1.259712)

amount= 1,25,971.2 inr

Answer 2

Answer:

225971.2

Step-by-step explanation:

p= 100000

R= 8%

N= 3

compound interest = P [1+ R/100]^N

C.I = 100000 [ 1+8/100]^3

C.I = 100000 [ 108/100]^3

C.I = 100000(108/100 x 108/100 x 108/100)

C.I = 1259712/10

C.I= 125971.2

Amount = C.I + Principal

= 125971.2 +100000

Amount = 225971.2