A school boy, travelling at 3 km/h, reaches his school 32 min late, but if he travels at 5 km/h, then he reaches his school 28 min early. Find the dis- rance then he travels every day to reach the school.
Answers
Step-by-step explanation:
Let the Distance between School and Home be : D
When Boys Travels with a Speed of 3 km/hr, He Reaches his School in \bf{: (\frac{D}{3})hr}:(3D)hr
When Boys Travels with a Speed of 5 km/hr, He Reaches his School in \bf{: (\frac{D}{5})hr}:(5D)hr
Given : If the Boys Travels at 3 km/h, He reaches his School 32 Minutes Late and if he Travels at 5 km/h, He reaches his School 28 Minutes Early.
It means : The Difference between the Time Taken by the Boy while travelling at Speed 3 km/hr and while travelling at Speed 5 km/hr should be Equal to (32 + 28) = 60 Minutes.
\bf{\implies (\frac{D}{3} - \frac{D}{5}) = 60\;Minutes}⟹(3D−5D)=60Minutes
\bf{\implies (\frac{D}{3} - \frac{D}{5}) = 1\;Hour}⟹(3D−5D)=1Hour
\bf{\implies (\frac{5D - 3D}{15}) = 1}⟹(155D−3D)=1
\bf{\implies (\frac{2D}{15}) = 1}⟹(152D)=1
\bf{\implies 2D = 15}⟹2D=15
\bf{\implies D = 7.5}⟹D=7.5
Distance Between School and His Home is 7.5 km