Question

a school club has a swimming pool that measures 22 m by 16 m that it is want to build a steel railing around the pool and leave 10 metre space between the railing and the pool for a dark area how much revealing will be needed

Answer 1

Answer:

2*10+22= 42

2*0+16=32

p= 2(l+b)

=2(42+36)

= 2*78

= 156 Ans

Answer 2

Answer:

A steel railing around the pool and leave 10 metre space between the railing and the pool for a dark area how much revealing will be needed is 156 m.

Step-by-step explanation:

Step 1: The units used to measure length vary. There are two types of length units: standard units and non-standard units. Standard units are ones that can be translated to other units and have a fixed, determined value. Centimeters, inches, metres, yards, and other units are some examples of standard units. Units that differ from person to person are considered non-standard. Measurements made using handspan, foot span, cubit, etc. are examples of non-standard units.

Step 2: Identifying the length of the supplied object is the definition of measuring length. Objects are provided length as a quantitative property so that they may be identified and handled with ease.

Step 3: Add $10 \mathrm{~m}$ twice to both the length and the width to get the dimensions of the fence.

$L=22+2 \cdot 10=22+20=42 \mathrm{~m}$

$w=16+2 \cdot 10=16+20=36 \mathrm{~m}$

So then the length of fencing is the perimeter of this largen rectangle,

$P=2 L+2 W=2 \cdot(42\}+2 \cdot(36)=84+72=156 \mathrm{~m}$

Learn more about questions visit:

https://brainly.in/question/25169033?referrer=searchResults

https://brainly.in/question/19586238?referrer=searchResults

#SPJ3