Question

A school collected 2601 as fees from its students. If fee paid by each student and number students in the school were equal how many students were there in the school.​

Answer 1

Answer:

51

Step-by-step explanation:

So let the answer be x.

$x$ x $x$ = 2601

x² = 2601

x = √2601

x = 51

Hope it helps!!

Answer 2

Solution :-

Let Their were X students in The class.

As given That, Fee paid by Each Student is Equal to Number of Students .

So,

→ Fee Given by Each Student is = Rs.X

So,

→ Total Fees Collected by Total Students = x * x = Rs. x².

Now, Given That, Total Fees collected was Rs.2601.

So,

→ x² = 2601

Square - Root Both sides ,

→ x = √(2601)

→ x = √(3 * 3 * 17 * 17)

→ x = √[(3*3) * (17*17)]

→ x = √(3² * 17²)

Now, using √(a)² = a , we get ,

→ x = 3*17

→ x = 51. (Ans).

Hence, Their were 51 Students in The School..