Question

A school conducted a survey to find out how their students live from the school. Given below is the distance of the houses of six students from the school. Let us find their average distance from the school.
950m, 800m, 700m, 1.5km, 1km, 750 m.

Answer 1

Given: Distance of the houses of six students, i.e. 950m, 800m, 700m, 1.5km, 1km & 750 m.

To Find: The average distance from the school.

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To find the average, we must first express all the distances in the same units.

• 1 km = 100 m
• 1.5 km = 1500 m

   

As we know that:

$\dag \; \underline{\boxed{\frak{\purple{ Average = \dfrac{ \; Sum \; of \; all \; scores \;}{ \; Total \; number \; of \; scores \; } }}}}$

   

$\implies \sf{ Average = \dfrac{Sum \; of \; the \; distance \; between \; home \; and \; school}{Total \; number \; of \; students} }$

   

$\implies \sf{ \dfrac{ \; 950 + 800 + 700 + 1500 + 1000 + 150 \; }{ 6 } }$

   

$\implies \sf{ \dfrac{ \cancel{ \; 5700 \; } }{ \cancel{ 6 } } }$

   

$\implies \underline{\boxed{\orange{\sf{950 \; m}}}}$

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Final Answer:

The average distance at which the students live from the school is 950 m.

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Apologies for the mistakes!

Answer 2

$\underbrace{\sf{ \pink{ \: \: \star \: Average = \dfrac{addition \: of \: all \: scores}{number \: of \: scores } \: \: }}}$

Turning km into m:

> 1m = 1000m

> 1.5m = 1500m

$\\ \longrightarrow \tt{ \dfrac{950 + 800 + 700 + 1500 + 1000 + 750}{6}} \\ \\ \longrightarrow \tt{ \frac{ \cancel{5700}}{ \cancel{6}} = 950m }$

: . The average distance is 950m.