A school decided to award prizes to students for three values—discipline, cleanliness of environment and regularity in attendance. The number of students getting prizes in the categories are in the ratio 1:2:3. If product of ratios is 162,then— Find the number of students getting prizes for ecah value.
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Answered by
12
Let the no of prizes for each category be x, 2x,3x
A.to.Q
x(2x)(3x)=162
6x³=162
x³=27
x³=3³
On comparing
x=3
So no prizes for each value are3, 6,9
A.to.Q
x(2x)(3x)=162
6x³=162
x³=27
x³=3³
On comparing
x=3
So no prizes for each value are3, 6,9
ARYAanshul:
thank u so much☺
Answered by
6
let x 2x 3x be the childrens
atp
x ×2x×3x = 162
6x cube = 162
x cube = 27
x = root 27
x= 3
the no of students getting prizes for each value is 3 6 and 9
atp
x ×2x×3x = 162
6x cube = 162
x cube = 27
x = root 27
x= 3
the no of students getting prizes for each value is 3 6 and 9
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