Question

a school decided to award prizes to their students for three values honesty punctuality and obedience if the number of students getting price for Honda City punctuality and obedience are in the ratio 1:2:3 and their product is 162 find the number of student getting prizes for each value

Answer 1

HERE IS YOUR ANSWER...⬇⬇


$\boxed{SOLUTION}$ ➡


It is given,

Number of students getting price for honesty ,punctuality and obedience are in the ratio = 1:2:3

Let,

The number of student getting price for honesty = x

•°•The number of student getting price for punctuality = 2x

And,the number of student getting price for obedience = 3x


A.T.Q. ,

$x \times 2x \times 3x = 162 \\ \\ = > 6x {}^{3} = 162 \\ \\ = > x {}^{3} = 162 \div 6 \\ \\ = > x {}^{3} = 27 \\ \\ = > x = \sqrt[3]{27} \\ \\ = > x = 3$



•°• The number of students getting price for honesty = x = 3

The number of students getting price for punctuality = 2x = 2 × 3 = 6

The number of students getting price for obedience = 3x = 3 × 3 = 9


$\boxed{ANSWER}$ ➡

The number of students getting price for honesty, punctuality and obedience are 3 , 6 and 9 respectively.



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Answer 2

Step-by-step explanation:

1=3

2=6

3=9.

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