Math, asked by kumardhana4288, 7 months ago

A School football team played 20 matches in one season . It won 26/40 of them how many matches did it lose

Answers

Answered by Anonymous
6

Given,

Total matches = 20

Winning matches = 26/40 of the total matches

To find,

The total number of losing matches.

Solution,

First of all, we have simplify the fractional value of the winning matches.

Winning matches fraction = 26/40 = 13/20

Winning matches number = 20 × 13/20 = 13

Losing matches = Total matches - winning matches = 20-13 = 7

(This mathematical problem is based upon the fractional calculations which is thoroughly demonstrated in the above calculations.)

Hence, they lose 7 matches.

Answered by reddyvritika27
0

Answer:

7 matches

Step-by-step explanation:

Given,

Total matches = 20

Winning matches = 26/40 of the total matches

To find,

The total number of losing matches.

Solution,

First of all, we have simplify the fractional value of the winning matches.

Winning matches fraction = 26/40 = 13/20

Winning matches number = 20 × 13/20 = 13

Losing matches = Total matches - winning matches = 20-13 = 7

(This mathematical problem is based upon the fractional calculations which is thoroughly demonstrated in the above calculations.)

Hence, they lose 7 matches.

Similar questions