Math, asked by AayushKumarGupta11, 1 year ago

a school has a hall which is 22 M long and 15.5 M broad. a carpet is laid inside the hall living all around a margin of 75 cm from the wall. find the area of the carpet and the area of the stripped left uncovered if the width of the carpet is 82 cm. find its cost at the rate of 60 rupees per metre:::: Brain lieated question::::::::::::::

Answers

Answered by chirag8874695183
834
Solution:-
Length = 22 m and Breadth = 15.5 m
The area of the hall = L × B = 22 × 15.5 = 341 m²
Margin of carpet = 75 cm = 0.75 m
Area of carpet = (22 - 2 × 0.75) (15.5 - 2 × 0.75)
⇒ (22 - 1.5) (15.5 - 1.5)
Area of the carpet = 20.5 × 14 = 287 m²
Portion uncovered = 341 - 287 = 54 m²
A meter length of the carpet = 1 m × 0.82 m = 0.82 m²
287/0.82 = 350 m of carpet
Cost of fencing the strip = Rs.60 per meter
Cost of fencing the strip = 350 × 60
= Rs. 21000
if my answer is helpful for you then please mark as brain liest
Answered by jkgaming2631
86

Step-by-step explanation:

Solution:-

Length = 22 m and Breadth = 15.5 m

The area of the hall = L × B = 22 × 15.5 = 341 m²

Margin of carpet = 75 cm = 0.75 m

Area of carpet = (22 - 2 × 0.75) (15.5 - 2 × 0.75)

⇒ (22 - 1.5) (15.5 - 1.5)

Area of the carpet = 20.5 × 14 = 287 m²

Portion uncovered = 341 - 287 = 54 m²

A meter length of the carpet = 1 m × 0.82 m = 0.82 m²

287/0.82 = 350 m of carpet

Cost of fencing the strip = Rs.60 per meter

Cost of fencing the strip = 350 × 60

= Rs. 21000

if my answer is helpful for you then please mark as brain liest

Similar questions