Question

a school has a strength of 3000 students

Answer 1

Hello Mate!!!

Solition ➡ Central angle of english =
360° - ( 90° + 36° + 126° )
360° - ( 126° + 126° )
360° - 252°
108°

Frequency/ Total frequency × 360° = Central Angle

Ley the frequency be x

x/ 3000 × 360 ° = 108°
x = 108° × 3000 × 1/360°
x = 108° × 100× 1/12
x = 900

So, 900 students like english

Hope it helps!☺✌

Answer 2

Hello Mate!!!

Solition ➡ Central angle of english =

360° - ( 90° + 36° + 126° )

360° - ( 126° + 126° )

360° - 252°

108°

Frequency/ Total frequency × 360° = Central Angle

Ley the frequency be x

x/ 3000 × 360 ° = 108°

x = 108° × 3000 × 1/360°

x = 108° × 100× 1/12

x = 900

So, 900 students like english

Hope it helps!☺✌