A school has five houses A, B, C, D and E. A class has 23 students, 4 from house A, 8 from house B, 5 from house C, 2 from house D and rest from house E. A single student is selected at random to be the class monitor. The probability that the selected student is not from A,B and C is A.(4/23) B.(8/23) C.(6/23) D. (17/23)
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Step-by-step explanation:
Total number of students, n(S) = 23
Number of students in houses A,B and C
= 4+8+5 = 17
∴ Remaining students = 23 - 17 = 6 n(E) = 6
So, probability that the selected students is not from A,B and C
P(E)=236
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