Question

A school has rectangular playground, whose breadth is two-third of its length. Adjacent to this ground, a right Isosceles triangle shaped piece of land is there, which is to be developed as rose garden. A nearby hardware whole sale shop comes forward to donate 200m of wire.

Q1 If the total length of the wire required for fencing the ground is 630m. Form a linear equation, if the length of the ground is ‘’ metres.

Please give only correct answers ​

Answer 1

Answer:

Length + Breadth = 315 m

Step-by-step explanation:

Let us consider the ground to be in the form of a rectangle.

Fencing a ground covers only the outer part of the field and not the inner portion.

So length of wire required for fencing the ground would be the perimeter of that field.

Perimeter = Length of wire required

⇒ Perimeter = 630 m

We know that

Perimeter of rectangle = 2 (Length + Breadth)

Let

Length be ‘l’

Breadth be ‘b’

Substitute in the above equation

⇒ 2 (l + b) = 630 m

⇒ l + b = 630 ÷ 2

⇒ l + b = 315

∴ The linear equation would be ⟨l + b = 315⟩

Answer 2

Let x the breadth

length = 2/3

total meter wire 200

= 2/3*200 = 133.3333