Question

A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.​

Answer 1

Step-by-step explanation:

Shahil Kumar roll no.17

Class 9th. H science assignment complete

Answer 2

Answer:

Given, 

From figure,

Dimension of playground =(120 m×80 m) 

Area of rectangle ABCD=120×80=9600m2 

Area of rectangle ABFE 

=AB×BF=120×3=360m2 

Now, IH=CF=BC−BF=80−3=77 m

So, Area of rectangle GHIJ 

JI×IH=2×77=154m2

So, Area of Remaining ground rectangle GHIJ= Area of  rectangle ABCD− Area or rectangle ABFE− Area of rectangle GHIJ

=9600−360−154=9600−514=9086m2