Question

A school sent 480 students for class X examination and out of them 420 passed. Another school sent 550 students and out of them 495 students passed ? Which school gave better results. ​

Answer 1

So to find which school did it better we need to find the percentage of students who passed.

In School 1

Number of students sent for class X examination ⇒ 480

Number of students who passes in the examination ⇒ 420

Percentage of Students who passed ⇒ $\sf \frac{No.\ of \ students \ who \ passed }{No. \ of \ students\ who \ appeared \ for \ the\ exam } \times 100$

⇒ $\frac{420}{480} \times 100$

⇒ $\frac{7}{8} \times 100$

⇒ $\frac{700}{8}$

⇒ $87.5\%$

∴ 87.5% students passed in school 1.

___________________________________

In School 2

Number of students sent for class X examination ⇒ 550

Number of students who passes in the examination ⇒ 495

Percentage of Students who passed ⇒ $\sf \frac{No.\ of \ students \ who \ passed }{No. \ of \ students\ who \ appeared \ for \ the\ exam } \times 100$

⇒ $\frac{495}{550} \times 100$

⇒ $\frac{9}{10} \times 100$

⇒ $\frac{900}{10}$

⇒ $90\%$

∴ 90% students passed in school 2.

___________________________________

∴ School 2 gave better results than School 1.

___________________________________

Answer 2

Question

A school sent 480 students for class X examination and out of them 420 passed. Another school sent 550 students and out of them 495 students passed ? Which school gave better results.

Solution

One school sent 480 students out of which 420 passed.

Percentage of students passed

$( \frac{420}{480} \times 100)\% \\ = 87.5\%$

Another school sent 550 students out of which 495 passed.

Percentage of students passed

$( \frac{495}{550} \times 100)\% \\ = 90 \%$

Ans:- The students passed from first school secured 87.5% marks.

The students passed from second school secured 90% marks.

From here, we can say that the second school gave better result than first school.