Question

A school team won 6 games this year against 4 games won last year. What is the percent increase?​

Answer 1

Answer:

the ans is 20

Step-by-step explanation:

Games won this year =6

Games won last year =4

Increase in the number of games =6--4

=2

Total number of games played =6+4=10 Percentage increase =

2/10 × 100=20 percent

hope it helps

Answer 2

$\huge\underline\textbf{Answer:-}$

The increase in the number of wins or the amount of change =6 - 4 = 2

$Percentage \: increase = \: \frac{amount \: of \: change \: }{orginal \:amount \: or \: base } \times 100$

$= \frac{increase \: in \: the \: number \: of \: wins}{orginal \: number \: of \: wins} \times 100 = \frac{2}{4} \times 100 = 50$

Threrefore, the answer is 50