Question

a school team won 6 games this year against 4 games won last year what is the present increase​

Answer 1

Answer:

50%

Step-by-step explanation:

Games Won last year = 4

Games Won this year = 6

Increase in Games Won = 6 - 4 = 2

Increase Percentage = ( Increase / Original Value ) × 100

⇒ Increase % = ( 2 / 4 ) × 100

⇒ Increase % = 1/2 × 100 = 50 %

Therefore the percentage increase in the number of games won is 50%.

Answer 2

Step-by-step explanation:

If X be the first year's present ,

And y be the second year's present .

Then x-y =6-4=2

Let get the present of this year ,

So that

2/4×100

=50%

Thank you !

#. Astro