Question

A school team won 6 games this year against 4 games won last year.

What is the per cent increase?​

Answer 1

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Given that the school won 6 games this year against 4 won last year

Increase in number of wins = 6 – 4 = 2

Hence per cent increase = (2/4) × 100

= (1/2) × 100

= 50%

Thus the percentage increase in winning the games this year is 50%.

Answer 2

Answer:

Given that the school won 6 games this year against 4 won last year

Increase in number of wins = 6 – 4 = 2

Hence per cent increase = (2/4) × 100

= (1/2) × 100

= 50%

Thus the percentage increase in winning the games this year is 50%.

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Step-by-step explanation:

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