Question

a school team won 6 games this year against 4 games won last year .what is the percentage increase

Answer 1

Percentage increase formula = $\frac{Difference Between Original And New Value  }{Original Value}$

=$\frac{6-4(difference)}{4(original)}$

=$\frac{2}{4}$ x 100

= $\frac{2}{1}$ x 25

= 50%

Thyere fore  50% is the increase

Answer 2

$\huge\underline\textbf{Answer:-}$

The increase in the number of wins or the amount of change =6 - 4 = 2

$Percentage \: increase = \: \frac{amount \: of \: change \: }{orginal \:amount \: or \: base } \times 100$

$= \frac{increase \: in \: the \: number \: of \: wins}{orginal \: number \: of \: wins} \times 100 = \frac{2}{4} \times 100 = 50$

Threrefore, the answer is 50