Question

A school trip covered 1/3rd of the journey by boat,2/5th by train, 1/15th by bus and the
remaining distance of 7200 m by foot. What was the total distance? What is the difference between the distances covered by train and bus?

please give in a method not only the answer​

Answer 1

Answer:

$\huge\star \underline{ \boxed{ \purple{Answer}}}\star$

(i) the total distance is = 36000m or. 36 km.

(ii) difference between the distances covered by train and bus = 12000m or 12km.

Step-by-step explanation:

Given :-

A school trip covered 1/3rd of the journey by boat

2/5th by train, 1/15th by bus and the

2/5th by train, 1/15th by bus and theremaining distance of 7200 m by foot.

To find :-

What was the total distance?

What is the difference between the distances covered by train and bus ?

SOLUTION :-

Let the total journey be x

by boat + by train + by bus + by foot = total journey

➝$\sf{\dfrac{1}{3}x\:+\:\dfrac{2}{5}x\:+\:\dfrac{1}{15}x\:+\:7200m\:=\:x}$

Now taking LCM (15),

➝$\sf{\dfrac{5x\:+\:6x\:+\:x}{15}\:+\:7200\:=\:x}$

➝$\sf{\dfrac{12x}{15}\:=\:(x\:-\:7200)}$

➝$\sf{\dfrac{\cancel{12}x\:4}{\cancel{15}\:5}\:=\:(x\:-\:7200)}$

➝$\sf{\dfrac{4x}{5}\:=\:(x\:-\:7200)}$

On cross multiply, we get :-

➝$\sf{4x\:=\:5(x\:-\:7200)}$

➝$\sf{4x\:=\:5x\:-\:36000}$

change the positions of -36000 and 4x across the '=' symbol.

we get,

➝$\sf{5x\:-\:4x\:=\:36000}$

➝$\sf{x\:=\:36000m\:or\:36km}$

(ii)

distance covered by train = $\sf{\dfrac{2}{5}x}$

➝$\sf{\dfrac{2}{\cancel{5}}\:\times\:\cancel{36000}\:7200}$

➝$\sf{14400m}$

distance covered by bus = $\sf{\dfrac{1}{15}x}$

➝$\sf{\dfrac{1}{\cancel{15}}\:\times\:\cancel{36000}\:2400}$

➝$\sf{2400m}$

differenve between distance covered by train and bus =

➝ distance covered by train - disatance covered by bus

➝ 14400 - 2400

➝12000m

➝or 12km

$\Large\mathcal\pink{Hope \: it \: helps \: you\:friend}$

Answer 2

Answer:

ara yaar apna face dikhao na niche kya dekha raha ho