A school van is running along a highway with a speed of 20 / . m s Vennila is standing at a distance of 60 m from the highway (perpendicular distance) and is 500 m away from the van. Find the minimum speed Vennila must run at to catch the school van.
Answers
Answer:
speed =20/.ms
Explanation:
Question (complete):
A school van is running along a highway with a speed of 20 m/ s Vennila is standing at a distance of 60 m from the highway (perpendicular distance) and is 500 m away from the van. Find the minimum speed Vennila must run at to catch the school van.
Answer:
The minimum speed vennila must run at to catch the school van is 2.4 m/s.
Explanation:
Let the speed of the van be "V". "D" be the distance between Vennila, and the van. "d" be the perpendicular distance from the highway to Vennila. And "v" be the speed with which Vennila must run.
Given,
V = 20 m/s
d = 60 m
D = 500 m
To find,
speed of Vennila (v)
Logic,
To find the minimum speed of Vennila must run to catch the van is to finding the time taken(t) by the van to reach Vennila, which should be the time taken by venilla to run to the van.
So, we know that
D = Vt
⇒ 500 m = 20 m/s (t)
⇒ t = 500/20 sec
⇒ t = 25 sec
Now, this much amount of time should be taken by Vennila to catch the van.
i.e. d = vt
⇒ 60 m = v (25 s)
⇒ v = 60/25
⇒ v = 2.4 m/s
Therefore, the minimum speed vennila must run at to catch the school van is 2.4 m/s.
#SPJ3