Math, asked by sahibha3461, 1 year ago

a schoolyard contains only bicycles and 4 wheeled wagons. on tuesday, the total number of wheels in the schoolyard was 166. what could the possible number of bicycles?

Answers

Answered by mysticd
10
Hi ,

Let the number of bicycles = x

number of wagons = y

according to the problem given ,

2x + 4y = 166

divide each term with 2 , we get

x + 2y = 83

x = - 2y + 83 ---( 1 )

it is a linear equation in two variables .

i ) if y = 0 ,

x = 83

ii ) if y = 1 ,

x = 81 ,

iii ) if y = 2 ,

x = 79

iv ) if y = 41 ,

x = 1


Therefore ,

possible bicycles are 1 to 83 .

possible wagons are 0 to 41

I hope this helps you.

: )






ii )
Answered by Shaizakincsem
0

Let no of bicycles=x and wagon=y

So,

2x+4y=134

=> x+2y=67

as x and y should be integer.

x=odd no.

15 is the answer.


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