a schoolyard contains only bicycles and 4 wheeled wagons. on tuesday, the total number of wheels in the schoolyard was 166. what could the possible number of bicycles?
Answers
Answered by
10
Hi ,
Let the number of bicycles = x
number of wagons = y
according to the problem given ,
2x + 4y = 166
divide each term with 2 , we get
x + 2y = 83
x = - 2y + 83 ---( 1 )
it is a linear equation in two variables .
i ) if y = 0 ,
x = 83
ii ) if y = 1 ,
x = 81 ,
iii ) if y = 2 ,
x = 79
iv ) if y = 41 ,
x = 1
Therefore ,
possible bicycles are 1 to 83 .
possible wagons are 0 to 41
I hope this helps you.
: )
ii )
Let the number of bicycles = x
number of wagons = y
according to the problem given ,
2x + 4y = 166
divide each term with 2 , we get
x + 2y = 83
x = - 2y + 83 ---( 1 )
it is a linear equation in two variables .
i ) if y = 0 ,
x = 83
ii ) if y = 1 ,
x = 81 ,
iii ) if y = 2 ,
x = 79
iv ) if y = 41 ,
x = 1
Therefore ,
possible bicycles are 1 to 83 .
possible wagons are 0 to 41
I hope this helps you.
: )
ii )
Answered by
0
Let no of bicycles=x and wagon=y
So,
2x+4y=134
=> x+2y=67
as x and y should be integer.
x=odd no.
15 is the answer.
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