Question

A scientist is measuring the temperature change in a chemical compound, The temperature dropped 11 OF per hour from the original temperature, After 4 hours, the temperature was 90 OF, Find the compound's original temperatur

Answer 1

Answer:

134°F

Step-by-step explanation:

Given :

Rate of temperature drop of the compound = 11 degree fahrenheit per hour

The temperature of the compound after 4 hours = 90 degree fahrenheit

To Find :

The original temperature of the compound = ?

Solution :

The amount of temperature drop in 1 hour = 11 degree fahrenheit

So, the amount of temperature drop in 4 hours = 4 \times× 11 degree fahrenheit

= 44 degree fahrenheit

Since the temperature of the compound after 4 hours is given 90 degree fahrenheit , this is the temperature after a drop of 44 degree fahrenheit from the original temperature of the compound .

So the original temperature is :

= 90 degree fahrenheit + 44 degree fahrenheit

= 134 degree fahrenheit

Hence , the original temperature of the compound is 134 degree fahrenheit .

hope it helps :)

Answer 2

Answer:

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134°C is the answer

You Just Multiply The changes per hour and Time and then add To

ie, 44+90 = 134