Math, asked by kpparchuk23, 10 months ago

A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L. Assuming the volume of each drop is 0.05 mL, how many drops were added to the water? About what percent of the solution is acid? Round to the nearest hundredth of a percent.

Answers

Answered by gadakhsanket
8

Dear Student,

◆ Answer -

  • No of drops = 4 drops
  • Acid % ~ 0.17 %

● Explaination -

Volume of acid in final solution -

Acid = final volume - initial volume

Acid = 1.202 - 1.2

Acid = 0.002 L

Acid = 2 ml

No of drops of acid added to water -

No of drops = total acid / volume of each drop

No of drops = 2 / 0.05

No of drops = 4 drops

Percentage of acid in solution -

V/V % = acid / solution × 100

V/V % = 0.002 / 1.202 × 100

V/V % = 1/6

V/V % = 0.1667 %

V/V % ~ 0.17 %

Hope this helps you...

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