Math, asked by Backson05tms, 11 months ago

A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L. Assuming the volume of each drop is 0.05​ mL, how many drops were added to the​ water? About what percent of the acid solution is​ acid?

Answers

Answered by sonuvuce
0

Answer:

Drops of acid added = 40

% of acid in the solution = 0.1664%

Step-by-step explanation:

1.2 L = 1.2 × 1000 = 1200 mL

1.202 L = 1.202 × 1000 = 1202 mL

Let x drops of acid were added

Since one drop contains 0.05 mL of acid

Therefore x drop will have 0.05x mL of acid

Therefore

1200 + 0.05x = 1202

or, 0.05x = 1202 - 1200

               = 2

or x = 2/0.05 = 40

Therefore, 40 drops of acid were added

Since 2 mL of acid are there in 1202 mL of solution

Therefore, the % of acid in the solution

= (2/1202) × 100

= 0.1664%

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