A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L. Assuming the volume of each drop is 0.05 mL, how many drops were added to the water? About what percent of the acid solution is acid?
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Answer:
Drops of acid added = 40
% of acid in the solution = 0.1664%
Step-by-step explanation:
1.2 L = 1.2 × 1000 = 1200 mL
1.202 L = 1.202 × 1000 = 1202 mL
Let x drops of acid were added
Since one drop contains 0.05 mL of acid
Therefore x drop will have 0.05x mL of acid
Therefore
1200 + 0.05x = 1202
or, 0.05x = 1202 - 1200
= 2
or x = 2/0.05 = 40
Therefore, 40 drops of acid were added
Since 2 mL of acid are there in 1202 mL of solution
Therefore, the % of acid in the solution
= (2/1202) × 100
= 0.1664%
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