Math, asked by ravirajupr852, 3 months ago

A scientist named Bob was exposed to some radiations which caused him to oge backwards after he turned 40. Four years la current age and his daughter Bella's age are in the ratio 3:1.

Determine the ratio of Bob's and Bella's age four years before Bob turned 40​

Answers

Answered by justinponmalakkunnel
17

x= Bella's age

Four years later Bella's age and his daughter Bella's age are in the ratio 3:1.

= 36 : x

x= 36/3 = 12

ratio of Bob's and Bella's age four years before Bob turned 40

bobs age = 36

Bella's age = 8

ratio = 36:8 = 9:2

Answered by amitnrw
5

Given :  A scientist named Bob was exposed to some radiation which caused him to age backward after he turned 40.

Four years later, his current age and his daughter Bella's age are in the ratio 3:1.

Determine the ratio of Bob's and Bella's age four years before Bob turned 40.

Solution:

Age of  Bob = 40

Age of Daughter = D years

some radiation which caused him to age backward after he turned 40.

so Age of Scientist after 4 years = 40 - 4 = 36 years

Daughter Age = D + 4 Years

36 /( D + 4)  = 3/1

=> D + 4 = 12

=> D = 8

Four year before 40 also

Age of Bob = 40 - 4 = 36 years

Age of Daughter = 8 - 4 = 4  Years

Ratio   36 : 4

= 9 : 1

ratio of Bob's and Alice's age four years before Bob turned 40. is 9 : 1

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