Question

A scientist prepares 0.125 M sodium chloride stock solution. What volume of the stock solutionis required to prepare a 100 mL dilute solution of 0.05 M?

Answer 1

Answer:

using M1V1= M2V2

or, 0.125×V = 0.05×100

V= 0.05×100/0.125

Explanation:

V= 5000/125

= 400ml

Answer 2

Answer: We will use the formula M1V1=M2V2

Explanation:

Data:

M1=0.125
M2=0.05
V2=100

M1V1=M2V2
0.125V=0.05x100
0.125V=5
so V=5 divide by 0.125
Ans is 40mL