Question

A scooter accquires a volicity of 36 km/h in 10 second just after a start . calculate the acceleration of the scooter. ​

Answer 1

Answer:

1 m/$s^{2}$

Explanation:

u=0                [Start after rest]

v=36km/h=10m/s

t=10s

a=?

v=u+at

10=0+a(10)

10=10a

a=1 m/$s^{2}$

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