A scooter acquire 36km/h in 10 second just after the start. It takes 20 seconds to stop. Calculate the acceleration in the two cases.
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initial speed 0
final speed 36 km/h=36 *1000/3600=10 m/s
time 20 sec
a ?
so w e use 1st eq. of motion
v=u +at
10m/sec=0+a*20sec
10m/sec=a*20sec
10/20m/sec2=a
1/2 m/sec 2=a
final speed 36 km/h=36 *1000/3600=10 m/s
time 20 sec
a ?
so w e use 1st eq. of motion
v=u +at
10m/sec=0+a*20sec
10m/sec=a*20sec
10/20m/sec2=a
1/2 m/sec 2=a
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