A scooter acquired a velocity of 36km/h in 10 sec. just after start calculate the acceleration of the scooter.
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Answered by
4
v=u+at
36×5/18=0+10a
a=36×5/10×18
a=180/180=1
36×5/18=0+10a
a=36×5/10×18
a=180/180=1
Answered by
4
a=v-u/t
v=36km/hr
u=0
t=10 sec
then after equalling the values of v,u,t
a=36000/3600/10
=10/10=1m/sec
always remember to put the ans in standard units
v=36km/hr
u=0
t=10 sec
then after equalling the values of v,u,t
a=36000/3600/10
=10/10=1m/sec
always remember to put the ans in standard units
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