A scooter acquires a velocity of 36 kilometre per hour in 10 seconds just after it start it takes 20 second to stop calculate the acceleration in two cases
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Answer:
In case 1:
u=0
v=36 = 36× 5/18= 10m/s
t=10 sec
a= v-u/t
a= 10-0/10
a = 10/10
a= 1 ms-²
In case 2:
u= 10m/s
v=0
t=20 sec
a= v-u/t
a= 0-10/20
a= -10/20
a= -1/2
a= -0.5ms-²
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