A scooter acquires a velocity of 36 km/ h in 10 sec just after the start .It takes 20 sec to stop. calculate the acceleration in two cases
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Answer:
u=0
v= 36km/h=10m/s
t=10sec
a=(10-0)/10=1m/s^2
now, u=10m/s
v=0
t=10 sec
a=(0-10)/10
=-1m/s^2
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